Claim status
Speed not supported
In the record
GoFast recording: January 2015
Testable
Target altitude from range and viewing angle
Method
Resolve the vertical component of the line of sight
SKY & SEA / CASE FILE

GoFast: target at 4,029 m, not skimming the sea

Working the released angles gives a vertical drop of 3,591 m from the aircraft, putting the GoFast target at 4,029 m rather than just above the water.

The ocean appears to race behind the small target in GoFast. The recording also carries a range and a downward viewing angle. Those quieter details put the target thousands of metres above the water, changing the geometry of the apparent chase before its identity has been established.

Run the calculation
A green scanner illustration of a flying saucer above a desertAn unidentified signal is where the work begins.
01 / THE CLAIM

The sea appears to supply a speedometer

The claim is that GoFast records an object skimming the ocean at extraordinary speed. The visual argument is straightforward: the camera holds a small bright target near the centre while the textured surface rushes behind it. If the target and the water were almost the same distance away, their relative motion would be a useful clue to motion across the sea. That shared distance is the unmeasured premise in the immediate impression.

02 / THE CASE

The display supplies a different distance

AARO’s reconstruction uses numbers visible in the recording. At one analysed frame, the aircraft was at 7,620 metres, the slant range to the target was 7,408 metres, and the sensor pointed 29 degrees downward. Slant range runs along the camera’s line of sight. It is neither the target’s height nor the horizontal distance to it.

The target therefore occupied an intermediate layer between the aircraft and the ocean. A moving viewpoint can make a closer object shift against a more distant background even when that object has little motion of its own. The effect is familiar through a train window: nearby posts cross distant scenery quickly because the observer changes position.

The available video does not supply the aircraft’s absolute compass heading. AARO consequently examined a range of headings and wind relationships instead of announcing one exact target speed. Its finding was that the recording did not show anomalous performance. The analysis did not identify the object.

03 / THE COMPUTATION

Resolve the triangle before timing the target

The instrument asks the narrower question that the frame can answer: how high above the ocean is the target? Multiply the slant range by the sine of the depression angle to obtain the vertical drop from the aircraft. Subtract that drop from the aircraft’s altitude. The opening values give a drop of about 3,591 metres and a target altitude of about 4,029 metres. Treating that target as if it sat on the sea would move it downward by the height of an entire intervening air layer.

Increase the downward angle and the calculated target moves lower. Increase the range at the same angle and it also moves lower, because more of the longer sightline lies vertically below the aircraft. Increase only aircraft altitude and the target rises by the same amount. The controls preserve those relationships; they do not attach a propulsion system to the answer.

The working triangle treats the nearby ocean as a horizontal reference, matching this first-frame reconstruction. A below-surface answer under edited values means that the selected altitude, range and angle cannot all describe an airborne target in this triangle. It is a useful consistency check on a proposed reading of the display.

RUN THE NUMBERS

Recover the target’s altitude

The opening inputs are the first analysed GoFast frame. Edited values explore the same local right-triangle geometry.

Calculation inputs
m

Display-derived starting value. Add 100 m and the target altitude rises 100 m.

m

Display-derived starting value. A longer range lowers the target at a fixed downward angle.

°

Display-derived starting value. A steeper downward view lowers the target.

Target altitude4,029m

Subtracting the vertical sightline component places the opening target about four kilometres above the water.

Vertical drop from aircraft3,591 m

Only this part of the slant range points downward.

Working tape
  1. Angle in radians29 × 3.141593 × 0.005556 = 0.506145
  2. Vertical share of the sightlinesin(0.506145) = 0.48481
  3. Vertical drop below aircraft7,408 × 0.48481 = 3,591.469667
  4. Target altitude above ocean7,620 − 3,591.469667 = 4,028.530333
04 / THE FINDING

The background was farther away

The recorded geometry places the target about 4,029 metres above the ocean. The target and the water were at substantially different distances from the camera, removing the common-distance premise behind the dramatic visual speed estimate. Recovering motion then requires the camera’s movement, the target’s changing sightline and the wind.

An unidentified object can have an ordinary range of motion. Identification asks what produced the signal. Kinematics asks how the signal moved through space. GoFast remains instructive because a striking answer to the first question was being inferred from an unchecked answer to the second.

All Sky & Sea
Thin-lens geometry for a distant point source

Triangular UFO bokeh

Defocus spreads a point light 50.5 pixels wide, 0.253 mm at the sensor, in the aperture's shape. The triangle comes from the iris, not the sky.

Compare counts after dividing by traffic exposure

Bermuda Triangle rates

Per 100,000 voyages the region records 2 against 4 elsewhere, a rate ratio of 0.5×. Set the traffic yourself: a count without a denominator shows nothing.