Claim status
Latitude-dependent rotation is observed
In the record
Foucault’s public demonstration, 1851
Testable
Swing-plane direction against elapsed time and latitude
Method
Local vertical component of Earth’s angular velocity
FLAT EARTH / CASE FILE

Foucault pendulum: 7.52 °/h at 30° north

At 30° north, the ideal pendulum precesses clockwise at 7.52 °/h; over the selected interval its turn is 7.52 °.

A pendulum’s direction changes slowly against marks on the floor. The prediction is not the same everywhere: latitude changes the rate and crossing the equator reverses the direction.

Run the calculation
An engraved circular map with red horizon measurement linesA claim about the world should fit the whole world.
01 / THE CLAIM

A floor that feels still can still turn

The absence of a felt daily spin is often treated as evidence that Earth does not rotate. The pendulum asks a different question: does its swing direction drift against the floor by the amount predicted at that latitude?

02 / THE CASE

Rate and direction are the test

Foucault pendulums exhibit slow changes of swing direction relative to their surroundings. At a pole the ideal precession makes one turn per Earth rotation; at the equator the rotational contribution is zero. Intermediate latitudes give intermediate rates, with opposite directions in the two hemispheres.

A real suspension can introduce its own motion. An elliptical swing, an uneven support or a disturbed release can add drift. A useful comparison records latitude, elapsed time and swing-plane bearings and distinguishes those disturbances from the predicted rotational signal.

03 / THE COMPUTATION

Project the rotation onto the local vertical

Using the rounded 23.93-hour sidereal rotation period, the signed precession rate is 360 sin(φ) / 23.93 degrees per hour. Here positive means clockwise when viewed from above; southern latitudes are negative and give counterclockwise drift.

The full-turn period is 360 divided by the magnitude of that rate. At zero latitude there is no finite full-turn period: the tool reports that explicitly rather than dividing by zero. Elapsed turn is rate multiplied by hours; it is not reduced modulo 360, so long runs keep their completed revolutions.

This is the slow precession of the swing direction, not the seconds-long back-and-forth oscillation of the bob. Changing the pendulum length changes that oscillation period, not the leading latitude factor used here.

RUN THE NUMBERS

Predict the swing-plane drift

Latitude is signed: north positive, south negative. Positive output means clockwise viewed from above.

Calculation inputs
°

Moving toward a pole increases the magnitude; crossing the equator reverses direction.

h

Double the elapsed time and the accumulated signed angle doubles.

Signed precession rate7.52°/h

Positive is clockwise; negative is counterclockwise, viewed from above.

Accumulated signed turn7.52 °

The slow change in swing direction, not the back-and-forth swing angle.

Full precession turn47.86 h

360 ÷ |7.521939| = 47.86 h

Working tape
  1. Latitude × π ÷ 18030 × 0.017453 = 0.523599
  2. Sine of latitudesin(0.523599) = 0.5
  3. Signed turn per Earth rotation360 × 0.5 = 180
  4. Signed turn per hour180 ÷ 23.93 = 7.521939
  5. Rate × elapsed hours7.521939 × 1 = 7.521939
04 / THE FINDING

One instrument supplies a geographic prediction

The 30° north scenario produces about 7.52° of clockwise drift per hour and a full precession turn in about 47.86 hours. The same southern latitude reverses the sign without changing the magnitude.

Try the equator, then either pole. A latitude-independent mechanical push would not reproduce this entire pattern merely by matching one demonstration.

All Flat Earth
Tangent geometry on a sphere, without atmospheric refraction

Horizon distance

The water horizon sits 5,048 m away and an elevated target adds 11,288 m, giving 16.34 km of shared sightline. Set both heights and watch it move.

Parallel-arc length compared with polar projection radius

Flat Earth map distortion

A southern parallel of 7,076 km is drawn 23,580 km long on a north-polar disk, a 3.33× stretch. Move the latitude and watch the error grow with it.

Orthographic projection of an ideal circular disk

Flat disk eclipse shadow

A tilted disk throws an oval shadow 100 cm by 50 cm, an axis ratio of 0.5. A sphere casts a circle at every angle. Set the tilt and compare the edges.

Similar angles and a full-circle ratio

Eratosthenes experiment

A 7.2° shadow-angle difference across 800 km gives 40,000 km. The editable calculation shows how angular measurement error changes the circumference.