Claim status
Uniform disk scale not supported
In the record
Azimuthal equidistant projection documented in USGS mapping literature
Testable
Length of a specified latitude arc under both geometries
Method
Parallel-arc length compared with polar projection radius
FLAT EARTH / CASE FILE

Flat Earth map: 7,076 km drawn as 23,580 km, 3.33× stretch

A southern parallel measuring 7,076 km on a sphere is drawn 23,580 km long on a north-polar disk, stretching real distances by 3.33×.

A circular map with the North Pole at its centre can preserve real distances from that pole. Its meridians are orderly and its continents recognisable. The price appears when the measuring tape turns sideways. Keeping north–south distances correct does not keep the lengths of the latitude circles correct, especially south of the equator.

Run the calculation
An engraved circular map with red horizon measurement linesA claim about the world should fit the whole world.
01 / THE CLAIM

A familiar drawing becomes a physical surface

The claim is that a north-centred disk map can serve as the literal shape of the world because it places familiar continents in familiar directions. Some distances on such a map work well by construction. That success is treated as evidence that the rest of its distances need no separate examination.

A map can be useful while changing geometry. The meaningful question is what happens when one fixed scale must describe movement in every direction. If a drawing needs a different scale along different paths, reading all of it as one physical surface changes the lengths of those paths.

02 / THE CASE

Equidistant has a centre

The azimuthal equidistant projection preserves distance and direction from its chosen centre. In its north-polar form, meridians radiate outward and latitude circles become concentric rings. A point’s map radius is proportional to its distance along a meridian from the North Pole. This is a genuine and useful property, not a mistake in the map.

But the guarantee is tied to that centre. Cartographic documentation distinguishes the straight radial directions, where scale is true, from the growing distortion away from the centre in other directions. The same general tradeoff occurs in other projections: preserving one selected property does not preserve every area, direction, shape and distance.

A parallel of latitude makes a particularly clean test because it is a circle in both constructions. On the sphere, its radius shrinks toward either pole. On the north-polar map, its radius keeps increasing as latitude moves south. The northern and southern halves therefore cannot retain matching parallel lengths under one radial scale.

03 / THE COMPUTATION

Follow the parallel in both drawings

Choose a latitude and an angular span of longitude. The instrument follows the latitude circle, not the shortest flight route between its endpoints. For spherical Earth radius R and latitude φ, the parallel radius is R cos φ. On the north-centred equidistant map, the corresponding ring radius is R(π/2 − φ), with angles expressed in radians.

Multiply each radius by the chosen longitude span in radians to obtain the two arc lengths. At the opening example of 45 degrees south and a 90-degree longitude span, the spherical parallel arc is about 7,076 kilometres. The map arc, read using the true radial scale, is about 23,580 kilometres. The map stretches that same parallel arc by a factor of about 3.33.

Changing the longitude span lengthens or shortens both arcs in direct proportion, so the distortion factor stays the same at a given latitude. Changing latitude is what changes the disagreement. The northern comparison preset demonstrates why the map looks more convincing around its centre: at 45 degrees north, the factor is about 1.11.

The map’s centimetres are not in dispute. These kilometre values ask what those centimetres would mean if the radial scale were also valid sideways. A mapmaker handles the distinction by specifying the projection. Treating the page as a literal terrain model removes that distinction and turns a documented distortion into a prediction about travel.

RUN THE NUMBERS

Measure the same latitude arc on both maps

Select a latitude and longitude span. Compare travel along that parallel on a sphere with its north-polar equidistant map arc, using the map’s true radial scale.

Calculation inputs
°

Your selected parallel. Negative is south. Moving farther from the North Pole increases the sideways stretch.

°

Your selected arc. Doubling the span doubles both distances and leaves their ratio unchanged. These are parallel arcs, not shortest routes.

Sideways distance multiplier3.33×

A value above one means the map arc is stretched relative to the spherical parallel.

Arc along the spherical parallel7,076 km

Distance following the selected latitude circle on the sphere.

Arc on the disk at radial scale23,580 km

What the map arc would mean if its true radial scale also applied sideways.

Working tape
  1. Radians per degree3.141593 ÷ 180 = 0.017453
  2. Latitude in radians(-45) × 0.017453 = -0.785398
  3. Angular distance from the North Pole90 − (-45) = 135
  4. Pole distance in radians135 × 0.017453 = 2.356194
  5. Cosine of latitudecos(-0.785398) = 0.707107
  6. Longitude span in radians90 × 0.017453 = 1.570796
  7. Sphere radius × cosine latitude × span6,371.0084 × 0.707107 × 1.570796 = 7,076.41113
  8. Sphere radius × pole angle × span6,371.0084 × 2.356194 × 1.570796 = 23,579.749704
  9. Map arc ÷ sphere arc23,579.749704 ÷ 7,076.41113 = 3.332162
04 / THE FINDING

The missing scale returns in the southern arcs

At 45 degrees south, the north-polar equidistant map stretches a latitude arc by a factor of about 3.33 when read at its true radial scale. The 90-degree example becomes about 23,580 kilometres on the disk, compared with about 7,076 kilometres along the spherical parallel. Changing the arc length leaves that multiplier unchanged.

The projection preserves distances from the North Pole by allowing distances around its rings to expand. Those two directions cannot share one uniform scale. Its orderly meridians and recognisable continents make it useful as a map; their appearance does not remove the measurable sideways stretch.

All Flat Earth
Tangent geometry on a sphere, without atmospheric refraction

Horizon distance

The water horizon sits 5,048 m away and an elevated target adds 11,288 m, giving 16.34 km of shared sightline. Set both heights and watch it move.

Orthographic projection of an ideal circular disk

Flat disk eclipse shadow

A tilted disk throws an oval shadow 100 cm by 50 cm, an axis ratio of 0.5. A sphere casts a circle at every angle. Set the tilt and compare the edges.